結果
問題 | No.2677 Minmax Independent Set |
ユーザー |
|
提出日時 | 2024-03-16 04:44:01 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 282 ms / 2,000 ms |
コード長 | 3,115 bytes |
コンパイル時間 | 1,775 ms |
コンパイル使用メモリ | 178,532 KB |
実行使用メモリ | 59,180 KB |
最終ジャッジ日時 | 2024-09-30 03:50:25 |
合計ジャッジ時間 | 11,064 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 61 |
ソースコード
#include<bits/stdc++.h>using namespace std;using ll = long long;using pll = pair<ll, ll>;#define drep(i, cc, n) for (ll i = (cc); i <= (n); ++i)#define rep(i, n) drep(i, 0, n - 1)#define all(a) (a).begin(), (a).end()#define pb push_back#define fi first#define se secondmt19937_64 rng(chrono::system_clock::now().time_since_epoch().count());const ll MOD1000000007 = 1000000007;const ll MOD998244353 = 998244353;const ll MOD[3] = {999727999, 1070777777, 1000000007};const ll LINF = 1LL << 60LL;const int IINF = (1 << 30) - 1;template<typename T>struct edge{int from, to;T cost;int id;edge(){}edge(int to, T cost=1) : from(-1), to(to), cost(cost){}edge(int to, T cost, int id) : from(-1), to(to), cost(cost), id(id){}edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id){}};template<typename T>struct redge{int from, to;T cap, cost;int rev;redge(int to, T cap, T cost=(T)(1)) : from(-1), to(to), cap(cap), cost(cost){}redge(int to, T cap, T cost, int rev) : from(-1), to(to), cap(cap), cost(cost), rev(rev){}};template<typename T> using Edges = vector<edge<T>>;template<typename T> using weighted_graph = vector<Edges<T>>;template<typename T> using tree = vector<Edges<T>>;using unweighted_graph = vector<vector<int>>;template<typename T> using residual_graph = vector<vector<redge<T>>>;void solve(){int n; cin >> n;tree<int> T(n);for(int i=0; i<n-1; i++){int u, v; cin >> u >> v;u--; v--;T[u].pb(edge<int>(v));T[v].pb(edge<int>(u));}vector<vector<int>> dp1(n, vector<int>(2, 0));function<void(int, int)> dfs1 = [&](int v, int p){for(edge<int> e : T[v]) if(e.to != p){dfs1(e.to, v);}dp1[v][1] = 1;for(edge<int> e : T[v]) if(e.to != p){dp1[v][0] += dp1[e.to][1];dp1[v][1] += dp1[e.to][0];}dp1[v][1] = max(dp1[v][1], dp1[v][0]);}; dfs1(0, -1);vector<int> ans(n, 0);vector<vector<int>> dp2(n, vector<int>(2, 0));function<void(int, int)> dfs2 = [&](int v, int p){//calc ans{for(edge<int> e : T[v]) if(e.to != p) ans[v] += dp1[e.to][0];ans[v] += dp2[v][0]+1;}// calc dp2{int sum0 = dp2[v][1], sum1 = 1 + dp2[v][0];for(edge<int> e : T[v]) if(e.to != p){sum0 += dp1[e.to][1];sum1 += dp1[e.to][0];}for(edge<int> e : T[v]) if(e.to != p){dp2[e.to][0] = sum0 - dp1[e.to][1];dp2[e.to][1] = sum1 - dp1[e.to][0];dp2[e.to][1] = max(dp2[e.to][1], dp2[e.to][0]);}}for(edge<int> e : T[v]) if(e.to != p){dfs2(e.to, v);}}; dfs2(0, -1);int res = IINF;for(int v=0; v<n; v++) res = min(res, ans[v]);cout << res << '\n';}int main(){cin.tie(nullptr);ios::sync_with_stdio(false);int T=1;//cin >> T;while(T--) solve();}