結果
| 問題 | No.2715 Unique Chimatagram |
| コンテスト | |
| ユーザー |
june19312
|
| 提出日時 | 2024-04-05 21:36:25 |
| 言語 | PyPy3 (7.3.17) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 810 bytes |
| 記録 | |
| コンパイル時間 | 328 ms |
| コンパイル使用メモリ | 82,232 KB |
| 実行使用メモリ | 81,416 KB |
| 最終ジャッジ日時 | 2024-10-01 01:49:59 |
| 合計ジャッジ時間 | 5,528 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 30 WA * 10 |
ソースコード
N = int(input())
dic = {}
dic2 = {}
abc = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
for i in range(N):
S = list(input())
S.sort()
nex = "".join(S)
if nex in dic:
dic[nex] += 1
else:
dic[nex] = 1
for j in abc:
nex2 = S + [j]
nex2.sort()
nex3 = "".join(nex2)
if nex3 not in dic2:
dic2[nex3] = 1
else:
dic2[nex3] += 1
#print(dic)
#print(dic2)
for ind,val in dic.items():
if val == 1:
for j in abc:
nex2 = S + [j]
nex2.sort()
nex3 = "".join(nex2)
if nex3 in dic2 and dic2[nex3] == 1:
print(nex3)
exit()
print(-1)
june19312