結果
問題 | No.2719 Equal Inner Products in Permutation |
ユーザー | tokusakurai |
提出日時 | 2024-04-05 23:06:18 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 37 ms / 2,000 ms |
コード長 | 5,501 bytes |
コンパイル時間 | 2,380 ms |
コンパイル使用メモリ | 205,960 KB |
実行使用メモリ | 9,540 KB |
最終ジャッジ日時 | 2024-10-01 03:01:50 |
合計ジャッジ時間 | 6,561 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 1 ms
5,248 KB |
testcase_01 | AC | 1 ms
5,248 KB |
testcase_02 | AC | 1 ms
5,248 KB |
testcase_03 | AC | 2 ms
5,248 KB |
testcase_04 | AC | 2 ms
5,248 KB |
testcase_05 | AC | 1 ms
5,248 KB |
testcase_06 | AC | 2 ms
5,248 KB |
testcase_07 | AC | 1 ms
5,248 KB |
testcase_08 | AC | 2 ms
5,248 KB |
testcase_09 | AC | 2 ms
5,248 KB |
testcase_10 | AC | 2 ms
5,248 KB |
testcase_11 | AC | 2 ms
5,248 KB |
testcase_12 | AC | 2 ms
5,248 KB |
testcase_13 | AC | 2 ms
5,248 KB |
testcase_14 | AC | 2 ms
5,248 KB |
testcase_15 | AC | 30 ms
8,416 KB |
testcase_16 | AC | 36 ms
9,128 KB |
testcase_17 | AC | 21 ms
6,912 KB |
testcase_18 | AC | 33 ms
9,216 KB |
testcase_19 | AC | 28 ms
8,192 KB |
testcase_20 | AC | 19 ms
6,528 KB |
testcase_21 | AC | 33 ms
9,288 KB |
testcase_22 | AC | 26 ms
7,552 KB |
testcase_23 | AC | 23 ms
7,168 KB |
testcase_24 | AC | 19 ms
6,400 KB |
testcase_25 | AC | 37 ms
9,540 KB |
testcase_26 | AC | 35 ms
9,472 KB |
testcase_27 | AC | 35 ms
9,472 KB |
testcase_28 | AC | 36 ms
9,432 KB |
testcase_29 | AC | 34 ms
9,344 KB |
testcase_30 | AC | 35 ms
9,528 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #define rep(i, n) for (int i = 0; i < (n); i++) #define per(i, n) for (int i = (n)-1; i >= 0; i--) #define rep2(i, l, r) for (int i = (l); i < (r); i++) #define per2(i, l, r) for (int i = (r)-1; i >= (l); i--) #define each(e, v) for (auto &e : v) #define MM << " " << #define pb push_back #define eb emplace_back #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define sz(x) (int)x.size() using ll = long long; using pii = pair<int, int>; using pil = pair<int, ll>; using pli = pair<ll, int>; using pll = pair<ll, ll>; template <typename T> using minheap = priority_queue<T, vector<T>, greater<T>>; template <typename T> using maxheap = priority_queue<T>; template <typename T> bool chmax(T &x, const T &y) { return (x < y) ? (x = y, true) : false; } template <typename T> bool chmin(T &x, const T &y) { return (x > y) ? (x = y, true) : false; } template <typename T> int flg(T x, int i) { return (x >> i) & 1; } int pct(int x) { return __builtin_popcount(x); } int pct(ll x) { return __builtin_popcountll(x); } int topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); } int topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); } int botbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); } int botbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); } template <typename T> void print(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' '); if (v.empty()) cout << '\n'; } template <typename T> void printn(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cout << v[i] + x << '\n'; } template <typename T> void err_print(const vector<T> &v, T x = 0) { int n = v.size(); for (int i = 0; i < n; i++) cerr << v[i] + x << ' '; cerr << endl; } template <typename T> int lb(const vector<T> &v, T x) { return lower_bound(begin(v), end(v), x) - begin(v); } template <typename T> int ub(const vector<T> &v, T x) { return upper_bound(begin(v), end(v), x) - begin(v); } template <typename T> void rearrange(vector<T> &v) { sort(begin(v), end(v)); v.erase(unique(begin(v), end(v)), end(v)); } template <typename T> vector<int> id_sort(const vector<T> &v, bool greater = false) { int n = v.size(); vector<int> ret(n); iota(begin(ret), end(ret), 0); sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; }); return ret; } template <typename T> void reorder(vector<T> &a, const vector<int> &ord) { int n = a.size(); vector<T> b(n); for (int i = 0; i < n; i++) b[i] = a[ord[i]]; swap(a, b); } template <typename T> T floor(T x, T y) { assert(y != 0); if (y < 0) x = -x, y = -y; return (x >= 0 ? x / y : (x - y + 1) / y); } template <typename T> T ceil(T x, T y) { assert(y != 0); if (y < 0) x = -x, y = -y; return (x >= 0 ? (x + y - 1) / y : x / y); } template <typename S, typename T> pair<S, T> operator+(const pair<S, T> &p, const pair<S, T> &q) { return make_pair(p.first + q.first, p.second + q.second); } template <typename S, typename T> pair<S, T> operator-(const pair<S, T> &p, const pair<S, T> &q) { return make_pair(p.first - q.first, p.second - q.second); } template <typename S, typename T> istream &operator>>(istream &is, pair<S, T> &p) { S a; T b; is >> a >> b; p = make_pair(a, b); return is; } template <typename S, typename T> ostream &operator<<(ostream &os, const pair<S, T> &p) { return os << p.first << ' ' << p.second; } struct io_setup { io_setup() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout << fixed << setprecision(15); cerr << fixed << setprecision(15); } } io_setup; constexpr int inf = (1 << 30) - 1; constexpr ll INF = (1LL << 60) - 1; // constexpr int MOD = 1000000007; constexpr int MOD = 998244353; void solve() { ll N; cin >> N; if (N == 1) { cout << "-1\n"; return; } if (N == 5) { cout << "1 2 4 8 14 3 6 9 12 15 13 10 11 7 5 \n"; return; } ll S = N * (N + 1) / 2; ll X = (S % 2 == 0 ? S / 2 : (S - 3) / 2); vector<ll> col(N + 1, 0); // 0: S-X, 1: X per2(i, 1, N + 1) { if (X < i) continue; X -= i; col[i] = 1; } if (S % 2 == 1 && col[1] == 1) { int y = 2; while (col[y] == 0) y++; assert(y >= 6); col[3] = 1; col[y - 2] = 1; col[1] = 0; col[y] = 0; } if (S % 2 == 1 && col[2] == 1) { int y = 3; while (col[y] == 0) y++; assert(y >= 5); col[3] = 1; col[y - 1] = 1; col[2] = 0; col[y] = 0; } // err_print(col); vector<ll> ans(3 * N); rep(i, N) { ans[N + i] = 3 * (i + 1); if (col[i + 1] == 0) { ans[i] = 3 * i + 2; ans[2 * N + i] = 3 * i + 1; } else { ans[i] = 3 * i + 1; ans[2 * N + i] = 3 * i + 2; } } // err_print(ans); if (S % 2 == 1) { ans[0] = 1; ans[1] = 4; ans[2 * N] = 5; ans[2 * N + 1] = 2; } ll x = 0, y = 0; rep(i, N) x += ans[i] * ans[N + i]; rep(i, N) y += ans[N + i] * ans[2 * N + i]; // cerr << x MM y << endl; assert(x == y); print(ans); } int main() { int T = 1; // cin >> T; while (T--) solve(); }