#973257 (C++17) No.2744 Power! or +1

• 問題: No.2744 Power! or +1
• ユーザー: kenken714
• 提出日時: 2024-04-18 16:03:17
• 言語: C++17 (gcc 13.3.0 + boost 1.87.0)
• 結果: AC
• 実行時間: 1,084 ms / 3,000 ms
• コード長: 1,849 bytes
• コンパイル時間: 2,323 ms
• コンパイル使用メモリ: 200,416 KB
• 最終ジャッジ日時: 2025-02-21 03:01:33
• ジャッジサーバーID （参考情報）: judge1 / judge5

ファイルパターン	結果
sample	AC * 2
other	AC * 9

ソースコード

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#include "bits/stdc++.h"
using namespace std;
#define REP(i, n) for(ll i = 0;i < n;i++)
#define REPR(i, n) for(ll i = n;i >= 0;i--)
#define FOR(i, m, n) for(ll i = m;i < n;i++)
#define FORR(i, m, n) for(ll i = m;i >= n;i--)
#define REPO(i, n) for(ll i = 1;i <= n;i++)
#define ll long long
#define INF (ll)1ll << 60
#define MINF (-1 * INF)
#define ALL(n) n.begin(),n.end()
#define MOD (ll)1000000007
#define P pair<ll, ll>
ll d[410000]; // 結果
struct edge { ll to, cost; };
vector<edge> g[410000]; //隣接リスト to, cost
void dijkstra(ll a) { //だいくすとら！
    priority_queue<P, vector<P>, greater<P> > q;
    fill(d, d + 410000, INF);
    d[a] = 0;
    q.push(P(0, a));
    while (!q.empty()) {
        P p = q.top();
        q.pop();
        ll v = p.second;
        if (d[v] < p.first) continue;
        REP(i, g[v].size()) {
            edge e = g[v][i];
            if (d[e.to] > d[v] + e.cost) {
                d[e.to] = d[v] + e.cost;
                q.push(P(d[e.to], e.to));
            }
        }
    }
}
ll n, a, b, c, u = 210000;
int main(){
    cin >> n >> a >> b >> c;
    REP(i, n){
        g[i].push_back({(i + 1) % n, a});
        g[i + u].push_back({(i + 1) % n + u, a});
        ll now = i, cost = b;
        bool overn = false;
        if (i <= 1) continue;
        while(cost <= 4 * 1e10){
            now *= i;
            cost *= b;
            if (now >= n) overn = true;
            now %= n;
            g[i].push_back({(overn ? u + now : now), cost});
            g[u + i].push_back({u + now, cost});
        }
    }
    ll now = 1;
    bool overn = false;
    REPO(i, n - 1){
        now *= i;
        if (now >= n) overn = true;
        now %= n;
        g[i].push_back({(overn ? u + now : now), c});
        g[u + i].push_back({0, c});
    }
    dijkstra(1);
    cout << min(d[0], d[u]) << endl;
}
 
 
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