結果

問題 No.2750 Number of Prime Factors
ユーザー 👑 binap
提出日時 2024-05-10 21:32:48
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 2,858 bytes
コンパイル時間 3,895 ms
コンパイル使用メモリ 257,252 KB
最終ジャッジ日時 2025-02-21 12:19:09
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 18 WA * 1
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ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return
    os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : "");
    return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
// Sieve of Eratosthenes
// https://youtu.be/UTVg7wzMWQc?t=2774
struct Sieve {
int n;
vector<int> f, primes;
Sieve(int n=1):n(n), f(n+1) {
f[0] = f[1] = -1;
for (ll i = 2; i <= n; ++i) {
if (f[i]) continue;
primes.push_back(i);
f[i] = i;
for (ll j = i*i; j <= n; j += i) {
if (!f[j]) f[j] = i;
}
}
}
bool isPrime(int x) { return f[x] == x;}
vector<int> factorList(int x) {
vector<int> res;
while (x != 1) {
res.push_back(f[x]);
x /= f[x];
}
return res;
}
vector<pair<ll,int>> factor(ll x) {
vector<pair<ll,int>> res;
for (int p : primes) {
int y = 0;
while (x%p == 0) x /= p, ++y;
if (y != 0) res.emplace_back(p,y);
}
if (x != 1) res.emplace_back(x,1);
return res;
}
int num_of_divisors(long long x){
auto f = factor(x);
long long res = 1;
for(auto [p, val] : f){
res *= val + 1;
}
return res;
}
set<long long> divisors(long long x){
set<long long> se = {1};
auto f = factor(x);
for(auto [key, value] : f){
set<long long> old = se;
for(long long y : old){
rep(i, value + 1){
se.insert(y);
y *= key;
}
}
}
return se;
}
};
const int M = 50;
int main(){
vector<long long> p = {1,2,6,30,210,2310,30030,510510,9699690,223092870,6469693230,200560490130,7420738134810,304250263527210,13082761331670030
        ,614889782588491410,1001001001001001001};
long long n;
cin >> n;
rep(i, n){
if(p[i] > n){
cout << i - 1 << "\n";
break;
}
}
return 0;
}
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