結果
問題 | No.2751 429-like Number |
ユーザー |
👑 |
提出日時 | 2024-05-10 21:46:01 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,041 ms / 4,000 ms |
コード長 | 2,909 bytes |
コンパイル時間 | 3,951 ms |
コンパイル使用メモリ | 256,400 KB |
最終ジャッジ日時 | 2025-02-21 12:31:26 |
ジャッジサーバーID (参考情報) |
judge4 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 6 |
other | AC * 22 |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef vector<int> vi; typedef vector<long long> vl; typedef vector<vector<int>> vvi; typedef vector<vector<long long>> vvl; typedef long double ld; typedef pair<int, int> P; ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} // Sieve of Eratosthenes // https://youtu.be/UTVg7wzMWQc?t=2774 struct Sieve { int n; vector<int> f, primes; Sieve(int n=1):n(n), f(n+1) { f[0] = f[1] = -1; for (ll i = 2; i <= n; ++i) { if (f[i]) continue; primes.push_back(i); f[i] = i; for (ll j = i*i; j <= n; j += i) { if (!f[j]) f[j] = i; } } } bool isPrime(int x) { return f[x] == x;} vector<int> factorList(int x) { vector<int> res; while (x != 1) { res.push_back(f[x]); x /= f[x]; } return res; } vector<pair<ll,int>> factor(ll x) { vector<pair<ll,int>> res; for (int p : primes) { int y = 0; while (x%p == 0) x /= p, ++y; if (y != 0) res.emplace_back(p,y); } if (x != 1) res.emplace_back(x,1); return res; } int num_of_divisors(long long x){ auto f = factor(x); long long res = 1; for(auto [p, val] : f){ res *= val + 1; } return res; } set<long long> divisors(long long x){ set<long long> se = {1}; auto f = factor(x); for(auto [key, value] : f){ set<long long> old = se; for(long long y : old){ rep(i, value + 1){ se.insert(y); y *= key; } } } return se; } }; int main(){ Sieve sieve(100000); auto primes = sieve.primes; int q; cin >> q; vector<long long> a(q); cin >> a; vector<int> cnt(q); rep(i, q){ for(int p : primes){ while(a[i] % p == 0){ a[i] /= p; cnt[i]++; if(a[i] == 1) break; } } } rep(i, q){ if(a[i] != 1) cnt[i]++; if(cnt[i] == 3) cout << "Yes\n"; else cout << "No\n"; } return 0; }