結果
問題 | No.2766 Delicious Multiply Spice |
ユーザー |
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提出日時 | 2024-05-31 21:39:51 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 2,638 bytes |
コンパイル時間 | 5,107 ms |
コンパイル使用メモリ | 273,136 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-12-20 22:53:17 |
合計ジャッジ時間 | 6,038 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 8 |
other | AC * 31 |
ソースコード
#include<bits/stdc++.h>#include<atcoder/all>#define rep(i,n) for(int i=0;i<n;i++)using namespace std;using namespace atcoder;typedef long long ll;typedef vector<int> vi;typedef vector<long long> vl;typedef vector<vector<int>> vvi;typedef vector<vector<long long>> vvl;typedef long double ld;typedef pair<int, int> P;ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); returnos;}template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : "");return os;}template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){returntrue;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n -1 ? "\n" : " "); return os;}template<typename T> void chmin(T& a, T b){a = min(a, b);}template<typename T> void chmax(T& a, T b){a = max(a, b);}const long long e18 = 10000;int main(){long long n;cin >> n;map<long long, string> ma;auto dfs = [&](auto dfs, long long x) -> void{if((x - 1) % 2 == 0){if(ma.find((x - 1) / 2) == ma.end()){ma[(x - 1) / 2] = ma[x] + 'A';dfs(dfs, (x - 1) / 2);}}if((x - 1) % 3 == 0){if(ma.find((x - 1) / 3) == ma.end()){ma[(x - 1) / 3] = ma[x] + 'B';dfs(dfs, (x - 1) / 3);}}};dfs(dfs, n);string s = ma[1];reverse(s.begin(), s.end());cout << s << "\n";return 0;}