結果
問題 | No.130 XOR Minimax |
ユーザー |
|
提出日時 | 2024-06-17 21:37:50 |
言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 193 ms / 5,000 ms |
コード長 | 2,140 bytes |
コンパイル時間 | 1,778 ms |
コンパイル使用メモリ | 137,832 KB |
実行使用メモリ | 51,072 KB |
最終ジャッジ日時 | 2024-06-17 21:37:56 |
合計ジャッジ時間 | 5,438 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 21 |
ソースコード
#include <algorithm>#include <cassert>#include <cstdio>#include <cstdlib>#include <cstring>#include <cmath>#include <iostream>#include <numeric>#include <vector>#include <map>#include <set>#include <queue>#include <functional>#include <iomanip>using namespace std;using ll = long long;class range {private: struct I{int x;int operator*(){return x;}bool operator!=(I& lhs){return x<lhs.x;}void operator++(){++x;}};I i,n;public:range(int n_):i({0}),n({n_}){}range(int i_,int n_):i({i_}),n({n_}){}I& begin(){return i;}I& end(){return n;}};template<class T, class U> ostream& operator<<(ostream& os, const pair<T, U>& p){ return os << "{" << p.first << ", " << p.second << "}"; }template<typename T> ostream& operator<<(ostream& os, const vector<T>& obj) { os << "{"; for (const auto& e : obj) os << e << ", "; return os << "}";}template<typename T> ostream& operator<<(ostream& os, const set<T>& obj) { os << "set{"; for (const auto& e : obj) os << e << ", "; return os << "}";}template<typename T, typename U> ostream& operator<<(ostream& os, const map<T, U>& obj) { os << "map{"; for (const auto& e : obj) os << e << ", ";return os << "}"; }#ifdef ONLINE_JUDGE#define dump(expr) ;#else#define dump(expr) { cerr << "\033[33m#L" << __LINE__ << ": " << expr << "\033[39m" << endl; }#endifstruct T {T *zero, *one;T() : zero(nullptr), one(nullptr) {};};const int N = 31;ll dp(T* now, int h) {if (now == nullptr) return 0;if (now->zero && now->one) {dump(now << " " << h);return (1LL << h) + min(dp(now->zero, h - 1), dp(now->one, h - 1));}return dp(now->zero, h - 1) | dp(now->one, h - 1);}ll solve() {int n; cin >> n;T* par = new T();while (n--) {ll x; cin >> x;T* now = par;for (int i : range(N)) {if (x & (1LL << (N - 1 - i))) {if (now->one == nullptr) now->one = new T();now = now->one;} else {if (now->zero == nullptr) now->zero = new T();now = now->zero;}}}ll res = dp(par, N - 1);return res;}int main() {cout << fixed << setprecision(12);cout << solve() << endl;}