結果

問題 No.2437 Fragile Multiples of 11
ユーザー tassei903
提出日時 2024-06-20 14:40:26
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 77 ms / 2,000 ms
コード長 3,365 bytes
コンパイル時間 472 ms
コンパイル使用メモリ 82,096 KB
実行使用メモリ 75,152 KB
最終ジャッジ日時 2024-06-20 14:40:30
合計ジャッジ時間 4,426 ms
ジャッジサーバーID
(参考情報)
judge5 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 34
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ソースコード

diff #
プレゼンテーションモードにする

import sys
input = lambda :sys.stdin.readline()[:-1]
ni = lambda :int(input())
na = lambda :list(map(int,input().split()))
yes = lambda :print("yes");Yes = lambda :print("Yes");YES = lambda : print("YES")
no = lambda :print("no");No = lambda :print("No");NO = lambda : print("NO")
#######################################################################
n = ni()
X = [int(x) for x in input()]
m = 11
mod = 998244353
def solve(n, X):
dp = [[0 for i in range(4)] for i in range(m)]
dp[0][0] = 1
for i in range(n):
ndp = [[0 for i in range(4)] for i in range(m)]
ndp, dp = dp, ndp
for j in range(m):
for k in range(4):
p, q = k//2, k%2
if ndp[j][k] == 0:continue
for x in range(10):
np = p
nq = q
xj = x if (n-i-1) % 2 else (-x)%m
nj = (j + xj)%m
if (xj+j * 2)%m == 0 and p:continue
if x != 0:
np = 1
if q == 0 and x > X[i]:
continue
if x < X[i]:
nq = 1
nk = np*2 + nq
dp[nj][nk] += ndp[j][k]
dp[nj][nk] %= mod
return (dp[0][2]+dp[0][3])%mod
e0 = set()
e1 = {0}
def f(s, x):
return set([y * 10 + x for y in s])
def merge(s1, s2):
return s1 | s2
def solve_greedy(n, X):
dp = [[e0 for i in range(4)] for i in range(m)]
dp[0][0] = e1
for i in range(n):
ndp = [[set() for i in range(4)] for i in range(m)]
ndp, dp = dp, ndp
for j in range(m):
for k in range(4):
p, q = k//2, k%2
if len(ndp[j][k]) == 0:continue
for x in range(10):
np = p
nq = q
xj = x if (n-i-1) % 2 else (-x)%m
nj = (j + xj)%m
if (xj+j * 2)%m == 0 and p:continue
if x != 0:
np = 1
if q == 0 and x > X[i]:
continue
if x < X[i]:
nq = 1
nk = np*2 + nq
dp[nj][nk] = merge(dp[nj][nk], f(ndp[j][k], x))
#print(dp)
return dp[0]
def solve2(n, X):
dp = [[0 for i in range(4)] for i in range(m)]
dp[0][0] = 1
for i in range(n):
ndp = [[0 for i in range(4)] for i in range(m)]
ndp, dp = dp, ndp
#print(ndp)
for j in range(m):
for k in range(4):
p, q = k//2, k%2
if ndp[j][k] == 0:continue
for x in range(10):
np = p
nq = q
xj = x if (n-i) % 2 else (-x)%m
nj = (j + xj)%m
if x != 0:
np = 1
if q == 0 and x > X[i]:
continue
if x < X[i]:
nq = 1
nk = np*2 + nq
#print((j,p,q),(nj, np,nq))
dp[nj][nk] += ndp[j][k]
dp[nj][nk] %= mod
return (dp[0][2]+dp[0][3])%mod
print(solve(n, X))
#print(solve_greedy(n, X))
#print(solve2(n, X))
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