結果

問題 No.2790 Athena 3
ユーザー 👑 binapbinap
提出日時 2024-06-21 21:37:32
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 2,801 bytes
コンパイル時間 4,583 ms
コンパイル使用メモリ 264,832 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-21 21:37:38
合計ジャッジ時間 4,999 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 14
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef vector<vector<int>> vvi;
typedef vector<vector<long long>> vvl;
typedef long double ld;
typedef pair<int, int> P;
ostream& operator<<(ostream& os, const modint& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return
    os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : "");
    return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return
    true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder
    ::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n -
    1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
int main(){
int x1, y1;
int x2, y2;
int x3, y3;
cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
vector<pair<int, int>> d = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
auto calc = [&](int x1, int y1, int x2, int y2, int x3, int y3){
long double a = x2 - x1;
long double b = y2 - y1;
long double c = x3 - x1;
long double d = y3 - y1;
long double res = abs(a * d - b * c) / 2;
return res;
};
long double ans = 0;
for(auto [dy1, dx1] : d){
for(auto [dy2, dx2] : d){
for(auto [dy3, dx3] : d){
long double S = calc(x1 + dx1, y1 + dy1, x2 + dx2, y2 + dy2, x3 + dx3, y3 + dy3);
chmax(ans, S);
}
}
}
cout << setprecision(15);
cout << ans << "\n";
return 0;
}
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