#990142 (PyPy3) No.2790 Athena 3

• 問題: No.2790 Athena 3
• ユーザー: aldyas
• 提出日時: 2024-06-21 21:45:54
• 言語: PyPy3 (7.3.15)
• 結果: AC
• 実行時間: 47 ms / 2,000 ms
• コード長: 2,343 bytes
• コンパイル時間: 256 ms
• コンパイル使用メモリ: 82,600 KB
• 実行使用メモリ: 56,940 KB
• 最終ジャッジ日時: 2024-06-21 21:45:56
• 合計ジャッジ時間: 2,116 ms
• ジャッジサーバーID （参考情報）: judge5 / judge2

ファイルパターン	結果
sample	AC * 3
other	AC * 14

ソースコード

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import sys
from collections import defaultdict, deque, Counter
from heapq import heapify, heappush, heappop, merge
from bisect import bisect_right, bisect_left 
left_binser = lower_bound = bisect_left ; right_binser = upper_bound = bisect_right
from itertools import permutations, combinations, accumulate
# from math import lcm,gcd
# from math import comb, perm
# from functools import lru_cache
# from types import GeneratorType
MOD = 10**9 + 7
_MOD = 998244353
YES = "YES"
NO = "NO"
ALICE = "Alice"
BOB = "Bob"
def FLOOR_DIV(a, b) :
    return a // b
def CEIL_DIV(a, b) :
    return (a // b) + (not(not(a % b)))
def get() :
    return map(int, sys.stdin.readline().split())
def getone() :
    return int(sys.stdin.readline().strip())
def getstr() :
    return sys.stdin.readline().split()
def getonestr() :
    return sys.stdin.readline().strip()
def getarr() :
    return list(map(int, sys.stdin.readline().split()))
def _3d_ARRAY_SPAWN(i, j, k) :
    return [[[0 for _k in range(k)] for _j in range(j)] for _i in range(i)]
def _2d_ARRAY_SPAWN(i, j) :
    return [[0 for _j in range(j)] for _i in range(i)]
   
"""
"never doubt that u can't do this, cause it's an insult to ur determination"
by @deepakgoswami0552 10/03/2024
""" 
                                    
def solve() :
    ...
    # Solution here!
    def area(x1,y1, x2,y2, x3,y3) :
        return 0.5 * abs(x1*(y2 - y3) + x2*(y3 - y1) + x3*(y1 - y2))
    
    x1,y1,x2,y2,x3,y3 = get()
    ans = 0
    for conf in range(64) :
        conf1 = conf & 3
        conf2 = (conf >> 2) & 3 
        conf3 = (conf >> 4) & 3
        a1,a2,b1,b2,c1,c2 = x1,y1,x2,y2,x3,y3
        
        if conf1 == 0 : a1 += 1
        if conf1 == 1 : a1 -= 1
        if conf1 == 2 : a2 += 1
        if conf1 == 3 : a2 -= 1
        
        if conf2 == 0 : b1 += 1
        if conf2 == 1 : b1 -= 1
        if conf2 == 2 : b2 += 1
        if conf2 == 3 : b2 -= 1
        if conf3 == 0 : c1 += 1
        if conf3 == 1 : c1 -= 1
        if conf3 == 2 : c2 += 1
        if conf3 == 3 : c2 -= 1
        ans = max(ans, area(a1,a2, b1,b2, c1,c2))
    
    return ans
""""""
testcase = ""
# testcase = "multiple" # Multiple tc
if testcase == "multiple" :
    for i in range(int(input())) : 
        print(solve())
        # solve()
        ...
else :
    print(solve())
    # solve()
    ...
 
 
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