結果

問題 No.2790 Athena 3
ユーザー tenten
提出日時 2024-06-24 10:45:11
言語 Java
(openjdk 23)
結果
AC  
実行時間 64 ms / 2,000 ms
コード長 2,470 bytes
コンパイル時間 4,601 ms
コンパイル使用メモリ 78,680 KB
実行使用メモリ 37,276 KB
最終ジャッジ日時 2024-06-24 10:45:18
合計ジャッジ時間 4,806 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 14
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import java.io.*;
import java.util.*;
import java.util.function.*;
import java.util.stream.*;
public class Main {
public static void main(String[] args) throws Exception {
Scanner sc = new Scanner();
Point[] points = new Point[3];
for (int i = 0; i < 3; i++) {
points[i] = new Point(sc.nextInt(), sc.nextInt());
}
Point[] pattern = new Point[]{new Point(1, 0), new Point(-1, 0), new Point(0, 1), new Point(0, -1)};
double ans = 0;
for (int i = 0; i < 4; i++) {
points[0].add(pattern[i]);
for (int j = 0; j < 4; j++) {
points[1].add(pattern[j]);
for (int k = 0; k < 4; k++) {
points[2].add(pattern[k]);
ans = Math.max(ans, points[0].getSpace(points[1], points[2]));
points[2].draw(pattern[k]);
}
points[1].draw(pattern[j]);
}
points[0].draw(pattern[i]);
}
System.out.println(ans);
}
static class Point {
double x;
double y;
public Point(double x, double y) {
this.x = x;
this.y = y;
}
public void add(Point p) {
x += p.x;
y += p.y;
}
public void draw(Point p) {
x -= p.x;
y -= p.y;
}
public double getSpace(Point p1, Point p2) {
double ans = (p1.x - x) * (p2.y - y) - (p1.y - y) * (p2.x - x);
return Math.abs(ans) / 2;
}
}
}
class Scanner {
BufferedReader br;
StringTokenizer st = new StringTokenizer("");
StringBuilder sb = new StringBuilder();
public Scanner() {
try {
br = new BufferedReader(new InputStreamReader(System.in));
} catch (Exception e) {
}
}
public int nextInt() {
return Integer.parseInt(next());
}
public long nextLong() {
return Long.parseLong(next());
}
public double nextDouble() {
return Double.parseDouble(next());
}
public String next() {
try {
while (!st.hasMoreTokens()) {
st = new StringTokenizer(br.readLine());
}
} catch (Exception e) {
e.printStackTrace();
} finally {
return st.nextToken();
}
}
}
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