#993872 (PyPy3) No.2803 Bocching Star

• 問題: No.2803 Bocching Star
• ユーザー: hato336
• 提出日時: 2024-07-12 21:03:23
• 言語: PyPy3 (7.3.15)
• 結果: AC
• 実行時間: 859 ms / 2,000 ms
• コード長: 3,376 bytes
• コンパイル時間: 166 ms
• コンパイル使用メモリ: 82,088 KB
• 実行使用メモリ: 260,348 KB
• 最終ジャッジ日時: 2024-07-12 21:04:30
• 合計ジャッジ時間: 21,511 ms
• ジャッジサーバーID （参考情報）: judge5 / judge3

ファイルパターン	結果
sample	AC * 3
other	AC * 35

ソースコード

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import collections,sys,math,functools,operator,itertools,bisect,heapq,decimal,string,time,random
#sys.setrecursionlimit(10**9)
#sys.set_int_max_str_digits(0)
#input = sys.stdin.readline
#n = int(input())
#
#alist = []
#https://github.com/shakayami/ACL-for-python/blob/master/segtree.py
class segtree():
    n=1
    size=1
    log=2
    d=[0]
    op=None
    e=10**15
    def __init__(self,V,OP,E):
        self.n=len(V)
        self.op=OP
        self.e=E
        self.log=(self.n-1).bit_length()
        self.size=1<<self.log
        self.d=[E for i in range(2*self.size)]
        for i in range(self.n):
            self.d[self.size+i]=V[i]
        for i in range(self.size-1,0,-1):
            self.update(i)
    def set(self,p,x):
        assert 0<=p and p<self.n
        p+=self.size
        self.d[p]=x
        for i in range(1,self.log+1):
            self.update(p>>i)
    def get(self,p):
        assert 0<=p and p<self.n
        return self.d[p+self.size]
    def prod(self,l,r):
        assert 0<=l and l<=r and r<=self.n
        sml=self.e
        smr=self.e
        l+=self.size
        r+=self.size
        while(l<r):
            if (l&1):
                sml=self.op(sml,self.d[l])
                l+=1
            if (r&1):
                smr=self.op(self.d[r-1],smr)
                r-=1
            l>>=1
            r>>=1
        return self.op(sml,smr)
    def all_prod(self):
        return self.d[1]
    def max_right(self,l,f):
        assert 0<=l and l<=self.n
        assert f(self.e)
        if l==self.n:
            return self.n
        l+=self.size
        sm=self.e
        while(1):
            while(l%2==0):
                l>>=1
            if not(f(self.op(sm,self.d[l]))):
                while(l<self.size):
                    l=2*l
                    if f(self.op(sm,self.d[l])):
                        sm=self.op(sm,self.d[l])
                        l+=1
                return l-self.size
            sm=self.op(sm,self.d[l])
            l+=1
            if (l&-l)==l:
                break
        return self.n
    def min_left(self,r,f):
        assert 0<=r and r<=self.n
        assert f(self.e)
        if r==0:
            return 0
        r+=self.size
        sm=self.e
        while(1):
            r-=1
            while(r>1 and (r%2)):
                r>>=1
            if not(f(self.op(self.d[r],sm))):
                while(r<self.size):
                    r=(2*r+1)
                    if f(self.op(self.d[r],sm)):
                        sm=self.op(self.d[r],sm)
                        r-=1
                return r+1-self.size
            sm=self.op(self.d[r],sm)
            if (r& -r)==r:
                break
        return 0
    def update(self,k):
        self.d[k]=self.op(self.d[2*k],self.d[2*k+1])
    def __str__(self):
        return str([self.get(i) for i in range(self.n)])
#s = input()
n,s = map(int,input().split())
#for i in range(n):
#    alist.append(list(map(int,input().split())))
alist = list(map(int,input().split()))
b = []
for i in alist:
    b.append(i)
    b.append(i-s)
    b.append(i+s)
b = list(set(b))
b.sort()
d = {b[i]:i for i in range(len(b))}
ans = []
st = segtree([0 for i in range(len(b))],operator.add,0)
for i in alist:
    st.set(d[i],st.get(d[i])+1)
for i in range(n):
    if st.prod(d[alist[i]-s],d[alist[i]+s]+1) == 1:
        ans.append(i+1)
print(len(ans))
print(*ans)
 
 
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