結果
問題 | No.1060 素敵な宝箱 |
ユーザー | Sumitacchan |
提出日時 | 2020-05-22 21:57:24 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 8 ms / 2,000 ms |
コード長 | 3,302 bytes |
コンパイル時間 | 1,877 ms |
コンパイル使用メモリ | 178,552 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-10-05 17:15:51 |
合計ジャッジ時間 | 2,498 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | AC | 2 ms
5,248 KB |
testcase_03 | AC | 2 ms
5,248 KB |
testcase_04 | AC | 2 ms
5,248 KB |
testcase_05 | AC | 2 ms
5,248 KB |
testcase_06 | AC | 2 ms
5,248 KB |
testcase_07 | AC | 2 ms
5,248 KB |
testcase_08 | AC | 2 ms
5,248 KB |
testcase_09 | AC | 2 ms
5,248 KB |
testcase_10 | AC | 2 ms
5,248 KB |
testcase_11 | AC | 2 ms
5,248 KB |
testcase_12 | AC | 3 ms
5,248 KB |
testcase_13 | AC | 4 ms
5,248 KB |
testcase_14 | AC | 4 ms
5,248 KB |
testcase_15 | AC | 6 ms
5,248 KB |
testcase_16 | AC | 5 ms
5,248 KB |
testcase_17 | AC | 3 ms
5,248 KB |
testcase_18 | AC | 4 ms
5,248 KB |
testcase_19 | AC | 3 ms
5,248 KB |
testcase_20 | AC | 5 ms
5,248 KB |
testcase_21 | AC | 5 ms
5,248 KB |
testcase_22 | AC | 5 ms
5,248 KB |
testcase_23 | AC | 4 ms
5,248 KB |
testcase_24 | AC | 7 ms
5,248 KB |
testcase_25 | AC | 7 ms
5,248 KB |
testcase_26 | AC | 8 ms
5,248 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; /*#include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; template<typename T> using gpp_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; template<typename T, typename L> using gpp_map = tree<T, L, less<T>, rb_tree_tag, tree_order_statistics_node_update>; template<typename T> using gpp_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;*/ struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_; #define FOR(i, begin, end) for(int i=(begin);i<(end);i++) #define REP(i, n) FOR(i,0,n) #define IFOR(i, begin, end) for(int i=(end)-1;i>=(begin);i--) #define IREP(i, n) IFOR(i,0,n) #define Sort(v) sort(v.begin(), v.end()) #define Reverse(v) reverse(v.begin(), v.end()) #define all(v) v.begin(),v.end() #define SZ(v) ((int)v.size()) #define Lower_bound(v, x) distance(v.begin(), lower_bound(v.begin(), v.end(), x)) #define Upper_bound(v, x) distance(v.begin(), upper_bound(v.begin(), v.end(), x)) #define Max(a, b) a = max(a, b) #define Min(a, b) a = min(a, b) #define bit(n) (1LL<<(n)) #define bit_exist(x, n) ((x >> n) & 1) #define debug(x) cout << #x << "=" << x << endl; #define vdebug(v) { cout << #v << "=" << endl; REP(i_debug, v.size()){ cout << v[i_debug] << ","; } cout << endl; } #define mdebug(m) { cout << #m << "=" << endl; REP(i_debug, m.size()){ REP(j_debug, m[i_debug].size()){ cout << m[i_debug][j_debug] << ","; } cout << endl;} } #define Return(ans) { cout << (ans) << endl; return 0; } #define pb push_back #define f first #define s second #define int long long #define INF 1000000000000000000 template<typename T> istream &operator>>(istream &is, vector<T> &v){ for (auto &x : v) is >> x; return is; } template<typename T> ostream &operator<<(ostream &os, vector<T> &v){ for(int i = 0; i < v.size(); i++) { cout << v[i]; if(i != v.size() - 1) cout << endl; }; return os; } template<typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p){ cout << '(' << p.first << ',' << p.second << ')'; return os; } template<typename T> void Out(T x) { cout << x << endl; } template<typename T1, typename T2> void Ans(bool f, T1 y, T2 n) { if(f) Out(y); else Out(n); } using vec = vector<int>; using mat = vector<vec>; using Pii = pair<int, int>; using PiP = pair<int, Pii>; using PPi = pair<Pii, int>; using Pdi = pair<double, int>; using bools = vector<bool>; using pairs = vector<Pii>; //int dx[4] = {1,0,-1,0}; //int dy[4] = {0,1,0,-1}; //char d[4] = {'D','R','U','L'}; const int mod = 1000000007; //const int mod = 998244353; //#define Add(x, y) x = (x + (y)) % mod //#define Mult(x, y) x = (x * (y)) % mod signed main(){ int N, M; cin >> N >> M; mat A(N, vec(M)); cin >> A; vec S(M, 0); REP(i, N) REP(j, M) S[j] += A[i][j]; pairs p(N); REP(i, N){ int t = 0; REP(j, M) t += S[j] * A[i][j]; p[i] = Pii(t, i); } Sort(p); Reverse(p); mat cnt(2, vec(M, 0)); REP(i, N){ int i0 = p[i].s; REP(j, M) cnt[i % 2][j] += A[i0][j]; } int ans = 0; REP(i, M) ans += cnt[0][i] * cnt[0][i] - cnt[1][i] * cnt[1][i]; Out(ans); return 0; }