結果
| 問題 |
No.1060 素敵な宝箱
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2020-05-22 22:49:35 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 4,313 bytes |
| コンパイル時間 | 2,408 ms |
| コンパイル使用メモリ | 198,896 KB |
| 最終ジャッジ日時 | 2025-01-10 14:59:04 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 5 WA * 19 |
ソースコード
#include <bits/stdc++.h>
const long long INF = 1LL << 60;
const long long MOD = 1000000007;
const double PI = acos(-1.0);
#define rep(i, n) for (ll i = 0; i < (n); ++i)
#define rep1(i, n) for (ll i = 1; i <= (n); ++i)
#define rrep(i, n) for (ll i = (n - 1); i >= 0; --i)
#define perm(c) sort(ALL(c));for(bool c##p=1;c##p;c##p=next_permutation(ALL(c)))
#define ALL(obj) (obj).begin(), (obj).end()
#define RALL(obj) (obj).rbegin(), (obj).rend()
#define pb push_back
#define to_s to_string
#define len(v) (ll)v.size()
#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())
#define print(x) cout << (x) << '\n'
#define drop(x) cout << (x) << '\n', exit(0)
#define debug(x) cout << #x << ": " << (x) << '\n'
using namespace std;
using ll = long long;
typedef pair<ll, ll> P;
typedef vector<ll> vec;
typedef vector<vector<ll>> vec2;
typedef vector<vector<vector<ll>>> vec3;
template<class S, class T> inline bool chmax(S &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class S, class T> inline bool chmin(S &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
inline ll msb(ll v) { return 1 << (31 - __builtin_clzll(v)); }
inline ll devc(ll x, ll y) { return (x + y - 1) / y; }
inline ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
inline ll lcm(ll a, ll b) { return a * (b / gcd(a, b)); }
struct IoSetup {
IoSetup() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
cout << fixed << setprecision(10);
cerr << fixed << setprecision(10);
}
} iosetup;
template< typename T1, typename T2 >
ostream &operator << (ostream &os, const pair< T1, T2 > &p) {
os << p.first << " " << p.second;
return os;
}
template< typename T1, typename T2 >
istream &operator >> (istream &is, pair< T1, T2 > &p) {
is >> p.first >> p.second;
return is;
}
template< typename T1, typename T2, typename T3 >
ostream &operator << (ostream &os, const tuple< T1, T2, T3 > &t) {
os << get<0>(t) << " " << get<1>(t) << " " << get<2>(t);
return os;
}
template< typename T1, typename T2, typename T3 >
istream &operator >> (istream &is, tuple< T1, T2, T3 > &t) {
is >> get<0>(t) >> get<1>(t) >> get<2>(t);
return is;
}
template< typename T >
ostream &operator << (ostream &os, const vector< T > &v){
for (int i = 0; i < (int)v.size(); ++i) {
os << v[i] << (i + 1 != v.size() ? " " : "");
}
return os;
}
template< typename T >
istream &operator >> (istream &is, vector< T > &v){
for(T &in : v) is >> in;
return is;
}
/*--------------------------------- Tools ------------------------------------------*/
template< typename T >
vector<T> cumsum(const vector<T> &X){
vector<T> res(X.size() + 1, 0);
for(int i = 0; i < X.size(); ++i) res[i + 1] += res[i] + X[i];
return res;
}
template< typename S, typename T, typename F>
pair<T, T> bisearch(S left, T right, F f) {
while(abs(right - left) > 1){
T mid = (right + left) / 2;
if(f(mid)) right = mid;
else left = mid;
}
return {left, right};
}
template< typename S, typename T, typename F>
double trisearch(S left, T right, F f, int maxLoop = 90){
double low = left, high = right;
while(maxLoop--){
double mid_left = high / 3 + low * 2 / 3;
double mid_right = high * 2 / 3 + low / 3;
if(f(mid_left) >= f(mid_right)) low = mid_left;
else high = mid_right;
}
return (low + high) * 0.5;
}
/*------------------------------- Main Code Here -----------------------------------------*/
int main()
{
ll N, M;
cin >> N >> M;
vec2 A(N, vec(M));
cin >> A;
vec C(M, 0);
vec C_(M, 0);
rep(i, M) rep(j, N) C[i] += A[j][i], C_[i] += A[j][i];
auto score = [&](vec X) {
ll s = 0;
rep(i, M) s += (C[i] - X[i]) * (C[i] - X[i]);
return s;
};
vec select(N, 0);
ll point = score(vec(M, 0));
rep(turn, N){
ll tp = INF;
ll ans = -1;
rep(i, N){
if(select[i]) continue;
if(chmin(tp, score(A[i]))) ans = i;
}
if(turn % 2){
rep(i, M) C[i] -= A[ans][i];
}
select[ans] = 1;
}
ll you = score(vec(M, 0));
ll enj = 0;
rep(i, M) enj += (C_[i] - C[i]) * (C_[i] - C[i]);
print(you - enj);
return 0;
}