結果

問題 No.1718 Random Squirrel
ユーザー kaikey
提出日時 2021-12-18 21:13:59
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 428 ms / 2,000 ms
コード長 7,076 bytes
コンパイル時間 2,680 ms
コンパイル使用メモリ 229,104 KB
最終ジャッジ日時 2025-01-27 03:24:54
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include "bits/stdc++.h"
#include <random>
#define ALL(x) (x).begin(), (x).end()
#define RALL(x) (x).rbegin(), (x).rend()
#define SZ(x) ((lint)(x).size())
#define FOR(i, begin, end) for(lint i=(begin),i##_end_=(end);i<i##_end_;++i)
#define IFOR(i, begin, end) for(lint i=(end)-1,i##_begin_=(begin);i>=i##_begin_;--i)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
#define endk '\n'
using namespace std; typedef unsigned long long _ulong; typedef long long int lint; typedef long double ld; typedef pair<lint, lint> plint; typedef
    pair<ld, ld> pld;
struct fast_ios { fast_ios() { cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(20); }; } fast_ios_;
template<class T> auto add = [](T a, T b) -> T { return a + b; };
template<class T> auto f_max = [](T a, T b) -> T { return max(a, b); };
template<class T> auto f_min = [](T a, T b) -> T { return min(a, b); };
template<class T> using V = vector<T>;
using Vl = V<lint>; using VVl = V<Vl>;
template< typename T > ostream& operator<<(ostream& os, const vector< T >& v) {
for (int i = 0; i < (int)v.size(); i++) os << v[i] << (i + 1 != v.size() ? " " : "");
return os;
}
template< typename T >istream& operator>>(istream& is, vector< T >& v) {
for (T& in : v) is >> in;
return is;
}
template<class T> bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }
template <class T>
T div_floor(T a, T b) {
if (b < 0) a *= -1, b *= -1;
return a >= 0 ? a / b : (a + 1) / b - 1;
}
template <class T>
T div_ceil(T a, T b) {
if (b < 0) a *= -1, b *= -1;
return a > 0 ? (a - 1) / b + 1 : a / b;
}
template <class F> struct rec {
F f;
rec(F&& f_) : f(std::forward<F>(f_)) {}
template <class... Args> auto operator()(Args &&... args) const {
return f(*this, std::forward<Args>(args)...);
}
};
lint gcd(lint a, lint b) { if (b == 0) return a; else return gcd(b, a % b); }
lint digit(lint a) { return (lint)log10(a); }
lint e_dist(plint a, plint b) { return abs(a.first - b.first) * abs(a.first - b.first) + abs(a.second - b.second) * abs(a.second - b.second); }
lint m_dist(plint a, plint b) { return abs(a.first - b.first) + abs(a.second - b.second); }
bool check_overflow(lint a, lint b, lint limit) { if (b == 0) return false; return a > limit / b; } // a * b > c => true
void Worshall_Floyd(VVl& g) { REP(k, SZ(g)) REP(i, SZ(g)) REP(j, SZ(g)) chmin(g[i][j], g[i][k] + g[k][j]); }
const lint MOD1000000007 = 1000000007, MOD998244353 = 998244353, INF = 2e18;
lint dx[8] = { -1, 0, 1, 0, 1, -1, 1, -1 }, dy[8] = { 0, 1, 0, -1, -1, -1, 1, 1 };
bool YN(bool flag) { cout << (flag ? "YES" : "NO") << endk; return flag; } bool yn(bool flag) { cout << (flag ? "Yes" : "No") << endl; return flag; }
struct Edge {
lint from, to, cost;
Edge() {
}
Edge(lint u, lint v, lint c) {
cost = c;
from = u;
to = v;
}
bool operator<(const Edge& e) const {
return cost < e.cost;
}
};
struct WeightedEdge {
lint to;
lint cost;
WeightedEdge(lint v, lint c) {
to = v;
cost = c;
}
bool operator<(const WeightedEdge& e) const {
return cost < e.cost;
}
};
using WeightedGraph = V<V<WeightedEdge>>;
typedef pair<plint, lint> tlint;
typedef pair<ld, lint> _pld;
typedef pair<lint, tlint> qlint;
typedef pair<lint, string> valstr;
typedef pair<char, string> pchar;
template< typename Data, typename T >
struct ReRooting {
struct Node {
int to, rev;
Data data;
};
using F1 = function< T(T, T) >;
using F2 = function< T(T, Data) >;
vector< vector< Node > > g;
vector< vector< T > > ldp, rdp;
vector< int > lptr, rptr;
const F1 f1;
const F2 f2;
const T ident;
ReRooting(int n, const F1& f1, const F2& f2, const T& ident) :
g(n), ldp(n), rdp(n), lptr(n), rptr(n), f1(f1), f2(f2), ident(ident) {}
void add_edge(int u, int v, const Data& d) {
g[u].push_back({ v, (int)g[v].size(), d });
g[v].push_back({ u, (int)g[u].size() - 1, d });
}
T dfs(int idx, int par) {
while (lptr[idx] != par && lptr[idx] < g[idx].size()) {
auto& e = g[idx][lptr[idx]];
ldp[idx][lptr[idx] + 1] = f1(ldp[idx][lptr[idx]], f2(dfs(e.to, e.rev), e.data));
++lptr[idx];
}
while (rptr[idx] != par && rptr[idx] >= 0) {
auto& e = g[idx][rptr[idx]];
rdp[idx][rptr[idx]] = f1(rdp[idx][rptr[idx] + 1], f2(dfs(e.to, e.rev), e.data));
--rptr[idx];
}
if (par < 0) return rdp[idx][0];
return f1(ldp[idx][par], rdp[idx][par + 1]);
}
vector< T > solve() {
for (int i = 0; i < g.size(); i++) {
ldp[i].assign(g[i].size() + 1, 0);
rdp[i].assign(g[i].size() + 1, 0);
lptr[i] = 0;
rptr[i] = (int)g[i].size() - 1;
}
vector< T > ret;
for (int i = 0; i < g.size(); i++) {
ret.push_back(dfs(i, -1));
}
return ret;
}
};
int main() {
lint N, K;
cin >> N >> K;
VVl to(N);
REP(i, N - 1) {
lint u, v;
cin >> u >> v; u--; v--;
to[u].push_back(v);
to[v].push_back(u);
}
Vl arr(K);
cin >> arr;
Vl ined(N);
REP(i, K) {
arr[i]--;
ined[arr[i]] = 1;
}
lint cnt = 0;
V<plint> edges;
map<lint, lint> fx;
{
auto dfs = [&](auto&& dfs, lint curr, lint prv) -> lint {
lint res = ined[curr];
for (lint nxt : to[curr]) {
if (nxt == prv) continue;
res |= dfs(dfs, nxt, curr);
}
if (res && prv != -1) {
edges.push_back({ curr, prv });
edges.push_back({ prv, curr });
}
return ined[curr] = res;
};
dfs(dfs, arr[0], -1);
set<lint> st;
REP(i, N) {
if (ined[i]) {
cnt++;
st.insert(i);
}
}
for (lint v : st) fx[v] = SZ(fx);
REP(i, SZ(edges)) edges[i] = { fx[edges[i].first], fx[edges[i].second] };
}
ReRooting<lint, lint> dp(cnt, f_max<lint>, add<lint>, 0);
set<plint> _st;
for (plint v : edges) {
if (_st.count({ v.second, v.first })) continue;
dp.add_edge(v.first, v.second, 1);
_st.insert(v);
}
auto res = dp.solve();
Vl ans(N, INF);
REP(i, N) {
if (ined[i] == 0) continue;
ans[i] = SZ(edges) - res[fx[i]];
auto dfs = [&](auto&& dfs, lint curr, lint prv, lint depth) -> void {
for (lint nxt : to[curr]) {
if (nxt == prv) continue;
dfs(dfs, nxt, curr, depth + 1);
}
ans[curr] = ans[i] + depth;
};
for (lint nxt : to[i]) {
if (ined[nxt]) continue;
dfs(dfs, nxt, i, 1);
}
}
REP(i, N) {
cout << ans[i] << endk;
}
}
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