結果

問題 No.2208 Linear Function
ユーザー tipstar0125
提出日時 2023-02-23 15:28:56
言語 Python3
(3.13.1 + numpy 2.2.1 + scipy 1.14.1)
結果
AC  
実行時間 49 ms / 2,000 ms
コード長 3,672 bytes
コンパイル時間 333 ms
コンパイル使用メモリ 13,312 KB
実行使用メモリ 12,544 KB
最終ジャッジ日時 2024-07-23 10:58:24
合計ジャッジ時間 937 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 3
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

from __future__ import annotations
import array
import bisect
import fractions
import heapq
import itertools
import math
import random
import re
import string
import sys
import time
from collections import defaultdict, deque
from functools import lru_cache
sys.setrecursionlimit(10**6)
INF = 10**20
MOD = 10**9 + 7
def read_int_list():
    return list(map(int, input().split()))
def read_int():
    return int(input())
def read_str_list():
    return list(input().split())
def read_str():
    return input()
def is_prime(n: int) -> bool:
    if n < 2:
        return False
    i = 2
    ok = True
    while i * i <= n:
        if n % i == 0:
            ok = False
        i += 1
    return ok
def eratosthenes(n: int) -> list[bool]:
    is_prime_list = ([False, True] * (n // 2 + 1))[0 : n + 1]
    is_prime_list[1] = False
    is_prime_list[2] = True
    for i in range(3, n + 1, 2):
        if not (is_prime_list[i]):
            continue
        if i * i > n:
            break
        for k in range(i * i, n + 1, i):
            is_prime_list[k] = False
    return is_prime_list
def legendre(n: int, p: int) -> int:
    cnt = 0
    pp = p
    while pp <= n:
        cnt += n // pp
        pp *= p
    return cnt
def prime_factorize(n: int) -> defaultdict[int, int]:
    nn = n
    i = 2
    d: defaultdict[int, int] = defaultdict(int)
    while i * i <= n:
        while nn % i == 0:
            d[i] += 1
            nn //= i
        i += 1
    if nn != 1:
        d[nn] += 1
    return d
def make_divisors(n: int) -> list[int]:
    i = 1
    ret = []
    while i * i <= n:
        if n % i == 0:
            ret.append(i)
            if i != n // i:
                ret.append(n // i)
        i += 1
    ret.sort()
    return ret
def gcd(a: int, b: int) -> int:
    if a == 0:
        return b
    else:
        return gcd(b % a, a)
def lcm(a: int, b: int) -> int:
    return a * b // gcd(a, b)
def align_heap(A: list[int], start: int, end: int):
    k = start
    while True:
        if 2 * k + 2 < end:
            p = A[k]
            l = A[2 * k + 1]
            r = A[2 * k + 2]
            m = max(p, l, r)
            if m == p:
                break
            elif m == l:
                A[k], A[2 * k + 1] = A[2 * k + 1], A[k]
                k = 2 * k + 1
            else:
                A[k], A[2 * k + 2] = A[2 * k + 2], A[k]
                k = 2 * k + 2
        elif 2 * k + 1 < end:
            p = A[k]
            l = A[2 * k + 1]
            m = max(p, l)
            if m == p:
                break
            else:
                A[k], A[2 * k + 1] = A[2 * k + 1], A[k]
                k = 2 * k + 1
        else:
            break
def build_heap(A: list[int]):
    N = len(A)
    for x in range(N // 2 - 1, -1, -1):
        align_heap(A, x, N)
def heap_sort(A: list[int], M: int):
    build_heap(A)
    N = len(A)
    for i in range(N - 1, 0, -1):
        A[0], A[i] = A[i], A[0]
        align_heap(A, 0, i)
        if i == M:
            print(*A)
    print(*A)
@lru_cache
def f(x: int) -> int:
    if x == 0:
        return 0
    elif x == 1:
        return 1
    return f(x - 1) + f(x - 2)
def dfs(pos: int, G: list[list[int]], visited: list[bool], is_chosen: list[bool]):
    ok = True
    for nxt in G[pos]:
        if not visited[nxt]:
            visited[nxt] = True
            dfs(nxt, G, visited, is_chosen)
            ok &= not is_chosen[nxt]
    is_chosen[pos] = ok
def solve():
    L, R, A, B = read_int_list()
    if A > 0:
        print(A * R + B)
    else:
        print(A * L + B)
def main():
    # solve()
    t = read_int()
    for _ in range(t):
        solve()
main()
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