結果
問題 | No.1621 Sequence Inversions |
ユーザー | akua |
提出日時 | 2023-04-20 12:57:45 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 317 ms / 3,000 ms |
コード長 | 5,878 bytes |
コンパイル時間 | 5,948 ms |
コンパイル使用メモリ | 236,016 KB |
実行使用メモリ | 52,740 KB |
最終ジャッジ日時 | 2024-11-15 04:16:45 |
合計ジャッジ時間 | 14,020 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 167 ms
52,740 KB |
testcase_01 | AC | 166 ms
52,740 KB |
testcase_02 | AC | 166 ms
52,672 KB |
testcase_03 | AC | 166 ms
52,612 KB |
testcase_04 | AC | 283 ms
52,608 KB |
testcase_05 | AC | 165 ms
52,608 KB |
testcase_06 | AC | 165 ms
52,608 KB |
testcase_07 | AC | 168 ms
52,736 KB |
testcase_08 | AC | 317 ms
52,736 KB |
testcase_09 | AC | 308 ms
52,660 KB |
testcase_10 | AC | 310 ms
52,736 KB |
testcase_11 | AC | 313 ms
52,736 KB |
testcase_12 | AC | 309 ms
52,608 KB |
testcase_13 | AC | 310 ms
52,708 KB |
testcase_14 | AC | 306 ms
52,612 KB |
testcase_15 | AC | 296 ms
52,704 KB |
testcase_16 | AC | 262 ms
52,576 KB |
testcase_17 | AC | 291 ms
52,580 KB |
testcase_18 | AC | 257 ms
52,616 KB |
testcase_19 | AC | 166 ms
52,708 KB |
testcase_20 | AC | 195 ms
52,704 KB |
testcase_21 | AC | 294 ms
52,572 KB |
testcase_22 | AC | 295 ms
52,616 KB |
testcase_23 | AC | 297 ms
52,704 KB |
testcase_24 | AC | 166 ms
52,612 KB |
testcase_25 | AC | 165 ms
52,484 KB |
testcase_26 | AC | 167 ms
52,708 KB |
testcase_27 | AC | 167 ms
52,576 KB |
testcase_28 | AC | 165 ms
52,612 KB |
ソースコード
#pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #include <atcoder/all> #include <iostream> // cout, endl, cin #include <string> // string, to_string, stoi #include <vector> // vector #include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound #include <utility> // pair, make_pair #include <tuple> // tuple, make_tuple #include <cstdint> // int64_t, int*_t #include <cstdio> // printf #include <map> // map #include <queue> // queue, priority_queue #include <set> // set #include <stack> // stack #include <deque> // deque #include <unordered_map> // unordered_map #include <unordered_set> // unordered_set #include <bitset> // bitset #include <cctype> // isupper, islower, isdigit, toupper, tolower #include <math.h> #include <iomanip> #include <functional> using namespace std; using namespace atcoder; #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define repi(i, a, b) for (int i = (int)(a); i < (int)(b); i++) typedef long long ll; typedef unsigned long long ull; const ll inf=1e18; using graph = vector<vector<int> > ; using P= pair<ll,ll>; using vi=vector<int>; using vvi=vector<vi>; using vll=vector<ll>; using vvll=vector<vll>; using vp=vector<P>; using vvp=vector<vp>; using vd=vector<double>; using vvd =vector<vd>; //string T="ABCDEFGHIJKLMNOPQRSTUVWXYZ"; //string S="abcdefghijklmnopqrstuvwxyz"; //g++ main.cpp -std=c++17 -I . //cout <<setprecision(20); //cout << fixed << setprecision(10); //cin.tie(0); ios::sync_with_stdio(false); const double PI = acos(-1); int vx[]={0,1,0,-1,-1,1,1,-1},vy[]={1,0,-1,0,1,1,-1,-1}; void putsYes(bool f){cout << (f?"Yes":"No") << endl;} void putsYES(bool f){cout << (f?"YES":"NO") << endl;} void putsFirst(bool f){cout << (f?"First":"Second") << endl;} void debug(int test){cout << "TEST" << " " << test << endl;} ll pow_pow(ll x,ll n,ll mod){ if(n==0) return 1; x%=mod; ll res=pow_pow(x*x%mod,n/2,mod); if(n&1)res=res*x%mod; return res; } ll gcd(ll x,ll y){ if(y==0)return x; return gcd(y,x%y); } ll lcm(ll x,ll y){ return ll(x/gcd(x,y))*y; } template<class T> bool chmin(T& a, T b) { if (a > b) { a = b; return true; } else return false; } template<class T> bool chmax(T& a, T b) { if (a < b) { a = b; return true; } else return false; } // https://youtu.be/L8grWxBlIZ4?t=9858 // https://youtu.be/ERZuLAxZffQ?t=4807 : optimize // https://youtu.be/8uowVvQ_-Mo?t=1329 : division ll mod =998244353; //ll mod =1e9+7; struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, const mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} // combination mod prime // https://www.youtube.com/watch?v=8uowVvQ_-Mo&feature=youtu.be&t=1619 struct combination { vector<mint> fact, ifact; combination(int n):fact(n+1),ifact(n+1) { //assert(n < mod); fact[0] = 1; for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i; ifact[n] = fact[n].inv(); for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i; } mint operator()(int n, int k) { if (k < 0 || k > n) return 0; if (n<0) return 0; return fact[n]*ifact[k]*ifact[n-k]; } mint p(int n, int k) { return fact[n]*ifact[n-k]; } } c(2000000); using vm=vector<mint> ; using vvm=vector<vm> ; struct edge{ int to; ll cost; edge(int to,ll cost) : to(to),cost(cost){} }; using ve=vector<edge>; using vve=vector<ve>; struct Compress{ vll a; map<ll,ll> d,d2; int cnt; Compress() :cnt(0) {} void add(ll x){a.push_back(x);} void init(){ set<ll>s(a.begin(),a.end()); for(auto y:s)d[y]=cnt++; for(auto&y:a)y=d[y]; for(auto u:d)d2[u.second]=u.first; } ll to(ll x){return d[x];} //変換先 ll from(ll x){return d2[x];}//逆引き int size(){return cnt;} }; vll anss; const int N=105; mint dp[N*N][N]; mint dpsum[N*N][N]; void solve(int test){ int n,k; cin >> n >> k; vi a(n);rep(i,n)cin >> a[i]; Compress comp; rep(i,n)comp.add(a[i]); comp.init(); rep(i,n)a[i]=comp.to(a[i]); vi cnt(n); sort(a.rbegin(),a.rend()); dpsum[0][1]=1; { rep(j,n*(n-1)/2+1)repi(last,1,n+1)dpsum[j][last]+=dpsum[j][last-1]; } cnt[a[0]]++; repi(i,2,n+1){ rep(j,n*(n-1)/2+1)repi(last,1,i+1){ if(cnt[a[i-1]]==0){ int prej=j-(last-1); if(prej>=0)dp[j][last]+=dpsum[prej][n]; else dp[j][last]=0; } else { int prej=j-(last-1-cnt[a[i-1]]); if(prej>=0 && last!=1)dp[j][last]+=dpsum[prej][last-1]; else dp[j][last]=0; } } cnt[a[i-1]]++; rep(j,n*(n-1)/2+1)repi(last,1,n+1)dpsum[j][last]=0; rep(j,n*(n-1)/2+1)repi(last,1,n+1)dpsum[j][last]=dpsum[j][last-1]+dp[j][last]; rep(j,n*(n-1)/2+1)repi(last,1,i+1)dp[j][last]=0; } mint ans=dpsum[k][n]; cout << ans << endl; } //g++ main.cpp -std=c++17 -I . int main(){cin.tie(0);ios::sync_with_stdio(false); int t=1;//cin >> t; rep(test,t)solve(test); for(auto u:anss)cout << u << endl; }