結果
問題 | No.2293 無向辺 2-SAT |
ユーザー |
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提出日時 | 2023-05-05 22:06:17 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 568 ms / 4,000 ms |
コード長 | 2,894 bytes |
コンパイル時間 | 4,268 ms |
コンパイル使用メモリ | 255,896 KB |
最終ジャッジ日時 | 2025-02-12 18:18:44 |
ジャッジサーバーID (参考情報) |
judge4 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 53 |
ソースコード
#include<bits/stdc++.h>#include<atcoder/all>using namespace std;using namespace atcoder;namespace shobon {// Implement (union by size) + (path compression)// Reference:// Zvi Galil and Giuseppe F. Italiano,// Data structures and algorithms for disjoint set union problemsstruct dsu {public:dsu() : _n(0) {}explicit dsu(int n) : _n(n), parent_or_size(n, -1) {}int _n;std::vector<int> parent_or_size;int merge(int a, int b) {assert(0 <= a && a < _n);assert(0 <= b && b < _n);int x = leader(a), y = leader(b);if (x == y) return x;if (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y);parent_or_size[x] += parent_or_size[y];parent_or_size[y] = x;return x;}bool same(int a, int b) {assert(0 <= a && a < _n);assert(0 <= b && b < _n);return leader(a) == leader(b);}int leader(int a) {assert(0 <= a && a < _n);if (parent_or_size[a] < 0) return a;return parent_or_size[a] = leader(parent_or_size[a]);}int size(int a) {assert(0 <= a && a < _n);return -parent_or_size[leader(a)];}std::vector<std::vector<int>> groups() {std::vector<int> leader_buf(_n), group_size(_n);for (int i = 0; i < _n; i++) {leader_buf[i] = leader(i);group_size[leader_buf[i]]++;}std::vector<std::vector<int>> result(_n);for (int i = 0; i < _n; i++) {result[i].reserve(group_size[i]);}for (int i = 0; i < _n; i++) {result[leader_buf[i]].push_back(i);}result.erase(std::remove_if(result.begin(), result.end(),[&](const std::vector<int>& v) { return v.empty(); }),result.end());return result;}};} // namespace atcodertypedef modint998244353 mint;typedef long long ll;int main(){int n, q; cin >> n >> q;vector<pair<int,int>> stack;shobon::dsu uf(2*n);mint ans = mint(2).pow(n);mint inv2 = mint(2).inv();for (int i=0; i<q; i++){int t; cin >> t;if (t == 2){int x, y; cin >> x >> y;x--; y--;stack.push_back(pair(x, n+y));stack.push_back(pair(y, n+x));if (!uf.same(x, n+y)) ans *= inv2;uf.merge(x, n+y);uf.merge(y, n+x);if (uf.same(x, n+x)) ans = 0;if (uf.same(y, n+y)) ans = 0;}else if(t == 1){int x,y; cin >> x >> y;x--; y--;stack.push_back(pair(x, y));stack.push_back(pair(n+y, n+x));if (!uf.same(x, y)) ans *= inv2;uf.merge(x, y);uf.merge(n+y, n+x);if (uf.same(x, n+x)) ans = 0;if (uf.same(y, n+y)) ans = 0;}else{for (auto [u,v]: stack){uf.parent_or_size[u] = -1;uf.parent_or_size[v] = -1;}stack.clear();ans = mint(2).pow(n);}cout << ans.val() << endl;}}