結果
問題 | No.2381 Gift Exchange Party |
ユーザー | nikaj |
提出日時 | 2023-07-14 21:52:02 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 62 ms / 2,000 ms |
コード長 | 2,630 bytes |
コンパイル時間 | 1,652 ms |
コンパイル使用メモリ | 161,176 KB |
実行使用メモリ | 7,408 KB |
最終ジャッジ日時 | 2024-09-16 06:47:54 |
合計ジャッジ時間 | 4,065 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 22 |
ソースコード
#include <bits/stdc++.h> using namespace std; #define F0(i,n) for (int i=0; i<n; i++) #define F1(i,n) for (int i=1; i<=n; i++) #define CL(a,x) memset(x, a, sizeof(x)); #define SZ(x) ((int)x.size()) const int inf = 1000009; const double pi = acos(-1.0); typedef pair<int, int> pii; typedef long long ll; const double EPS = 1e-9; const int MOD = 998244353; #define PR(x) cerr << #x << "=" << x << endl template<class A, class B> ostream& operator<<(ostream& os, const pair<A, B>& p) { os << "(" << p.first << ", " << p.second << ")"; return os; } template<class A, class B, class C> ostream& operator<<(ostream& os, const tuple<A, B, C>& p) { os << "(" << get<0>(p) << ", " << get<1>(p) << ", " << get<2>(p) << ")"; return os; } istream& operator>>(istream& is, pii& p) { is>>p.first>>p.second; return is; } template<class T> ostream& operator<<(ostream& os, const vector<T>& v) { os << "["; F0(i,SZ(v)) { if (i>0) os << ","; os << v[i]; } os << "]"; return os; } template<class T> ostream& operator<<(ostream& os, const set<T>& v) { os << "{"; int f=1; for(auto i:v) { if(f)f=0;else os << ","; cerr << i; } os << "}" << endl; return os; } template<class T, class R> ostream& operator<<(ostream& os, const map<T,R>& v) { os << "{"; int f=1; for(auto i:v) { if(f)f=0;else os << ", "; cerr << i.first << ":" << i.second; } os << "}" << endl; return os; } int i, j, k, n; ll m, ans; const int N = 200005; const int M = 435; int dp[N]; const int DX[]={-1,0,1,0}; const int DY[]={0,1,0,-1}; const string CS="nesw"; const string HS="URDL"; void Add(int& x, int y) { x += y; if (x >= MOD) x -= MOD; } ll Mult(int x, int y) { return 1LL * x * y % MOD; } ll modpow(ll x, ll n) { if (n == 0) return 1; ll y = modpow(x, n / 2); y = (y * y) % MOD; if (n & 1) y = (y * x) % MOD; return y; } const int MAXN = 200001; ll f[MAXN], rf[MAXN]; ll C(int n, int k) { return f[n] * rf[k] % MOD * rf[n - k] % MOD; } void Solve() { dp[0] = 1; F1(i, n) { dp[i] = dp[i - 1]; if (i >= m) { ll x = C(i - 1, m - 1); x = Mult(x, f[m - 1]); x = Mult(x, dp[i - m]); Add(dp[i], x); } } ans = f[n] - dp[n]; if (ans < 0) ans += MOD; cout << ans << endl; } int main() { //ignore = freopen("x.in", "r", stdin); //freopen("x.out", "w", stdout); //int tn; cin >> tn; //F1(ti, tn) { f[0] = rf[0] = 1; for (int i = 1; i <= 200000; i++) { f[i] = (f[i - 1] * i) % MOD; rf[i] = modpow(f[i], MOD - 2); } while (cin >> n >> m) { //PR(n); Solve(); } return 0; }